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AREA PROBLEMS

Area Problems
If the base of a rectangular is increased by 10% and the area is unchanged , then the corresponding altitude must to be decreased by?

11%
111/9 %
91/11 %
10%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let base = b and altitude = h Then, Area = b x h But New base = 110b / 100 = 11b / 10Let New altitude = HThen, Decrese = (h - 10h /11 )= h / 11? Required decrease per cent = (h/11) x (1 / h ) x 100 %= 91/11 %

Area Problems
The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is?

None of these
15 meters
3 meters
4 meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m

Area Problems
The cost of cultivating a square field at the rate of Rs. 160 per hectare is Rs. 1440. the cost of putting a fence around it at 75 paisa per meter is?

Rs. 1800
Rs. 810
Rs. 900
Rs. 360

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = 1440 / 160 hectares = 9 hectares = 90000 m2? One side = ?90000 m = 300 mSo perimeter = 4 x 300 m = 1200 m ? Cost of fencing = Rs (1200 x 75) / 100= Rs. 900

Area Problems
A rectangular plot is half as long again as it broad. The area of the lawn is 2/3 hectares. The length of the plot is?

100 meters
(100/ ? 3 ) meters
33 meters
66.66 meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = b meters. then, length = 3b/2 meters ? b x 3b/2 = 2/3 X 10000? b2 = (4 x 10000)/9? b = ( 2 X 100)/3 m ? Length = (3/2) x (2/3) x 100 m= 100 m

Area Problems
The ratio between the length and breadth of a rectangular field is 5:4. If the breadth is 20 meters less than the length, the perimeters of the field is?

none of these
260 m
280 m
360 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length of rectangular field = 5y,so width = 4y.From question5y - 4y = 20m? x = 20m ? Length = (5 x 20)m = 100 mBreadth = (4 x 20) m = 80 m ? Perimeter = 2 (100 + 80 ) m = 360 m

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