Stoichiometry An ideal gas can be liquified, because It gets solidified directly without becoming liquid Its critical temperature is more than 0°C Its molecular size is very small Forces operative between its molecules are negligible It gets solidified directly without becoming liquid Its critical temperature is more than 0°C Its molecular size is very small Forces operative between its molecules are negligible ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Pick out the wrong unit conversion of calorific value. 1 BTU/ft³ = 8.9 kcal/m³ = 0.038 MJ/m³ 1 kcal/m³ = 0.1124 BTU/ft³ 1 kcal/kg = 1.8 BTU/lb = 4.186 kJ/kg 1 BTU/lb = 2.3 kcal/kg 1 BTU/ft³ = 8.9 kcal/m³ = 0.038 MJ/m³ 1 kcal/m³ = 0.1124 BTU/ft³ 1 kcal/kg = 1.8 BTU/lb = 4.186 kJ/kg 1 BTU/lb = 2.3 kcal/kg ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Heat of neutralisation of a strong acid and strong base is always a constant value, i.e., 57 KJ/Kg mole. This is because The strong base and strong acid reacts in aqueous solution The strong base and strong acid reacts completely The salt formed does not hydrolyse Only OH⁻ and H⁺ ions react in every case The strong base and strong acid reacts in aqueous solution The strong base and strong acid reacts completely The salt formed does not hydrolyse Only OH⁻ and H⁺ ions react in every case ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry __________ equation relates latent heat and boiling point. Antonie Kopp's Trouton's Kistyakowsky Antonie Kopp's Trouton's Kistyakowsky ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry A vapor that exists above its critical temperature is termed as a __________ vapor. Unsaturated Gaseous Saturated Sub-cooled Unsaturated Gaseous Saturated Sub-cooled ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Heat of solution in a system in which both solute and solvent are liquids is termed as Standard integral heat of solution Heat of hydration Heat of mixing Heat of solvation Standard integral heat of solution Heat of hydration Heat of mixing Heat of solvation ANSWER DOWNLOAD EXAMIANS APP
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