Electric Circuits A voltage source having an open circuit voltage of 100 V and internal resistance of 50 Ω is equivalent to a current source 0.5 A in parallel with 50 Ω. 2 A with 50 Ω in series. 2 A with 50 Ω in parallel. none of these. 0.5 A in parallel with 50 Ω. 2 A with 50 Ω in series. 2 A with 50 Ω in parallel. none of these. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Capacitors for P.f correction are rated in KW. KVA. KV. KVAR. KW. KVA. KV. KVAR. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In above question, if circuit efficiency is 90 %. What will be output power ? 30 kW. 37.3 kW. 35.6 kW. 40 kW. 30 kW. 37.3 kW. 35.6 kW. 40 kW. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits The capacitance of a conductor is varying from 2 microfarad to zero in 1 sec linearly if the voltage applied to it is 6 V the energy stored in 0.5 sec in the condenser is 10 µ joules. 18 µ joules. 55.1 µ joules. 20 µ joules. 10 µ joules. 18 µ joules. 55.1 µ joules. 20 µ joules. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In the circuit shown in the figure the voltage across the 2 Ω resistor is 4 V. 1 V. 3 V. 2 V. 4 V. 1 V. 3 V. 2 V. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits The common voltage across parallel branches with different voltage sources can be determined by the relation V = (V1 / R1 + V2 / R2 + V3 / R3) / (1 / R1 + 1 / R2 +1 / R3 .....) The statement is associated with which theorem? Thevenin’s theorem. Superposition theorem. Millman’s theorem. Norton’s theorem. Thevenin’s theorem. Superposition theorem. Millman’s theorem. Norton’s theorem. ANSWER DOWNLOAD EXAMIANS APP
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