Electric Circuits A voltage source having an open circuit voltage of 100 V and internal resistance of 50 Ω is equivalent to a current source 2 A with 50 Ω in parallel. none of these. 0.5 A in parallel with 50 Ω. 2 A with 50 Ω in series. 2 A with 50 Ω in parallel. none of these. 0.5 A in parallel with 50 Ω. 2 A with 50 Ω in series. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A 230V, 50Hz voltage is applied to a coil having L = 5H and R = 2 Ohm in series with capacitance C. When the voltage across the coil is 400V, find the current in the circuit? 0.1578 A. 0.2547 A. 0.1465 A. 0.4583 A. 0.1578 A. 0.2547 A. 0.1465 A. 0.4583 A. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In the given figure the value of the source voltage is 30 V. 44 V. 12 V. 24 V. 30 V. 44 V. 12 V. 24 V. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Which of the following may be value of resistivity of copper? 1.7 X 10 - 4. 1.7 X 10 - 5. 1.7 X 10 - 6. 1.7 X 10 - 3. 1.7 X 10 - 4. 1.7 X 10 - 5. 1.7 X 10 - 6. 1.7 X 10 - 3. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Advantage of active filter is easy to tune. both of above. derive high impedance load. do not offer gain. easy to tune. both of above. derive high impedance load. do not offer gain. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits The common voltage across parallel branches with different voltage sources can be determined by the relation V = (V1 / R1 + V2 / R2 + V3 / R3) / (1 / R1 + 1 / R2 +1 / R3 .....) The statement is associated with which theorem? Thevenin’s theorem. Norton’s theorem. Superposition theorem. Millman’s theorem. Thevenin’s theorem. Norton’s theorem. Superposition theorem. Millman’s theorem. ANSWER DOWNLOAD EXAMIANS APP
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