Stoichiometry A solution is made by dissolving 1 kilo mole of solute in 2000 kg of solvent. The molality of the solution is 0.5 2 0.5 1 0.5 2 0.5 1 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry The weight fraction of methanol in an aqueous solution is 0.64. The mole fraction of methanol XM satisfies XM < 0.5 XM = 0.5 XM ≥ 0.64 0.5 < XM < 0.64 XM < 0.5 XM = 0.5 XM ≥ 0.64 0.5 < XM < 0.64 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Saturated solution of benzene in water is in equilibrium with a mixture of air and vapours of benzene and water at room temperature and pressure. Mole fraction of benzene in liquid is xB and the vapour pressures of benzene and water at these conditions are PvB and Pvw respectively. The partial pressure of benzene in air-vapour mixture is XB.Patm PvB (Patm - Pvw)xB XB.PvB XB.Patm PvB (Patm - Pvw)xB XB.PvB ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry The heat evolved in the combustion of benzene is represented by the equation: C₆H₆ + 7.5 O₂ = 6CO₂ + 3H₂O, ΔH = 3264.6 kJ/kg. mole The heat energy change, when 39 gm of C₆H₆ is burnt in an open container, will be __________ kJ/kgmole. +1632.3 +816.15 -2448.45 -1632.3 +1632.3 +816.15 -2448.45 -1632.3 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Pick out the wrong unit conversion of temperature. °R = 273 + °F °F = (°C + 17.778) x 1.8 Temperature difference of 1°K = 1°C = 9/5 °F °C = (F- 32) x 0.555 °R = 273 + °F °F = (°C + 17.778) x 1.8 Temperature difference of 1°K = 1°C = 9/5 °F °C = (F- 32) x 0.555 ANSWER DOWNLOAD EXAMIANS APP
Stoichiometry Which of the following expressions defines the Baume gravity scale for liquids heavier than water? 145 - (145/G) (400/G) - 400 200(G-1) (141.5/G) - 131.5 145 - (145/G) (400/G) - 400 200(G-1) (141.5/G) - 131.5 ANSWER DOWNLOAD EXAMIANS APP
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