Electrical Machines A smaller air gap in a induction motor helps to reduce the chance of crawling. increase the starting torque. reduce the chance of cogging. reduce the magnetizing current. reduce the chance of crawling. increase the starting torque. reduce the chance of cogging. reduce the magnetizing current. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The crawling in the induction motor is caused by harmonics developed in the motor high loads low voltage supply improper design of stator laminations harmonics developed in the motor high loads low voltage supply improper design of stator laminations ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a DC machine, which of these parameters remain the same whether it runs as a DC motor or a DC generator? Induced emf. Mechanical power. Can not be determined. Armature current. Induced emf. Mechanical power. Can not be determined. Armature current. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines During no load test, an induction motor draws power for core loss and copper loss. for copper loss and windage friction loss. only for the small copper loss. for core loss and windage and friction loss. for core loss and copper loss. for copper loss and windage friction loss. only for the small copper loss. for core loss and windage and friction loss. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A bipolar dc machine with interpoles has a main-pole flux of ф per pole and an interpole flux of Фᵢ per pole. The yoke of the machine is devide into four quadrants by the main-pole axis and The commutation axis. The flux-distribution in the quadrants will be ½ ( ф + фᵢ ) in two adjacent quadrants and ½ ( ф - фᵢ ) in the remaining two quadrants ½ ( ф + фᵢ ) in two diametrically opposite quadrants and ½ ( ф - фᵢ ) in the remaining two Quadrants ½ ( ф + фᵢ ) in all the four quadrants ½ ( ф - фᵢ ) in all the four quadrants ½ ( ф + фᵢ ) in two adjacent quadrants and ½ ( ф - фᵢ ) in the remaining two quadrants ½ ( ф + фᵢ ) in two diametrically opposite quadrants and ½ ( ф - фᵢ ) in the remaining two Quadrants ½ ( ф + фᵢ ) in all the four quadrants ½ ( ф - фᵢ ) in all the four quadrants ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In one 132 / 33 kV transformer the LV resistance is 0.02 per unit. The resistance referred to HV side is 0.16 pu. 0.01 pu. 0.08 pu. 0.02 pu. 0.16 pu. 0.01 pu. 0.08 pu. 0.02 pu. ANSWER DOWNLOAD EXAMIANS APP
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