SSC JE Electrical 2019 with solution SET-2
A series magnetic circuit will have

Same magnetic flux
Different magnetic flux
Total reluctance of a series circuit = difference of the reluctances in different parts of the circuit
Two or more paths for magnetic flux

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SSC JE Electrical 2019 with solution SET-2
If a circular conductor carries a current of ‘I’ ampere having radius ‘r’ meter, then the magnetizing force at the center of the coil is given by

(1/2r)*(At/m)
(1/4r)*(At/m)
(1/r)*(At/m)
(1/r)*(At/Wb)

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SSC JE Electrical 2019 with solution SET-2
IL = Load Current, then the relation between these currents for a DC series generator is

IL ÷ Ise ÷ Ia
IL ÷ Ise = Ia
IL = Ise = Ia
IL = Ise + Ia

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