Applied Mechanics and Graphic Statics A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be 3t² + 2t 6t - 2 3t³ - 2t 6t + 2 3t² + 2t 6t - 2 3t³ - 2t 6t + 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of a trapezoidal dam section whose top width is a, bottom width is band the vertical side is a, from its vertical face is (b² + bc + c²)/3 (b + c) None of these (a² + ab + b²)/3 (a + b) (a² + ab + c²)/3 (a + c) (b² + bc + c²)/3 (b + c) None of these (a² + ab + b²)/3 (a + b) (a² + ab + c²)/3 (a + c) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rope is wrapped twice around a rough pole with a coefficient of friction ‘A . It is subjected to a force Fj at one end and a gradually increasing force F2 is applied at the other end till the rope just starts slip-ping. At this instant the ratio of F2 to Fi is 1 e4* e2* e*72 1 e4* e2* e*72 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two forces are in equilibrium, then the forces must(i) Be equal in magnitude(ii) Be opposite in sense(iii) Act along the same line (i) and (iii) Only (i) (i) and (ii) All (i), (ii) and (iii) (i) and (iii) Only (i) (i) and (ii) All (i), (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Cartesian form of the equation of catenary is y = c sin x/c y = c sinh x/c y = c tan x/c y = c cosh x/c y = c sin x/c y = c sinh x/c y = c tan x/c y = c cosh x/c ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is P² + Q² + 2PQ tan θ P² + Q² + 2P sin θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2PQ tan θ P² + Q² + 2P sin θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS