Applied Mechanics and Graphic Statics A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be 6t + 2 3t² + 2t 3t³ - 2t 6t - 2 6t + 2 3t² + 2t 3t³ - 2t 6t - 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of a quadrant of a circle lies along its central radius at a distance of 0.6 R 0.3 R 0.4 R 0.2 R 0.6 R 0.3 R 0.4 R 0.2 R ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A cable loaded with 0.5 tonne per horizontal metre span is stretched between supports in the same horizontal line 400 m apart. If central dip is 20 m, the minimum tension in the cable, will be 200 tonnes at the centre 500 tonnes at the centre 200 tonnes at the left support 200 tonnes at the right support 200 tonnes at the centre 500 tonnes at the centre 200 tonnes at the left support 200 tonnes at the right support ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The phenomenon of collision of two elastic bodies takes place because bodies Attempt to regain its original shape due to their elasticities Immediately after collision come momentarily to rest All listed here Tend to compress each other till they are compressed maximum possible Attempt to regain its original shape due to their elasticities Immediately after collision come momentarily to rest All listed here Tend to compress each other till they are compressed maximum possible ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics In a simple screw jack, the pitch of the screw is 9 mm and length of the handle operating the screw is 45 cm. The velocity ratio of the system is 5 314 1.5 25 5 314 1.5 25 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If a particle moves with a uniform angular velocity ‘ω’ radians/sec along the circumference of a circle of radius ‘r’, the equation for the velocity of the particle, is v = ω √(r² + y²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(y² - r²) v = ω √(r² + y²) y = ω √(y - r) v = ω √(r² - y²) v = ω √(y² - r²) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS