Applied Mechanics and Graphic Statics A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be 3t² + 2t 3t³ - 2t 6t - 2 6t + 2 3t² + 2t 3t³ - 2t 6t - 2 6t + 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of a light string 4 m in length is fixed to a point on a smooth wall and the other end fastened to a point on the surface of a smooth sphere of diameter 2.25 m and of weight 100 kg. The tension in the string is 19.5 kg 22.5 kg 17.5 kg 25 kg 19.5 kg 22.5 kg 17.5 kg 25 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A satellite goes on moving along its orbit round the earth due to Gravitational force Centrifugal force Centripetal force None of these Gravitational force Centrifugal force Centripetal force None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The following factor affects the orbit of a satellite up to an altitude of 720 km from the earth's surface Gravity of the sun and the moon Uneven distribution of the gravitational field Aerodynamic forces None of these Gravity of the sun and the moon Uneven distribution of the gravitational field Aerodynamic forces None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A body A of mass 6.6 kg which is lying on a horizontal platform 4.5 m from its edge is connected to the end of a light string whose other end is supporting a body of mass 3.2 kg as shown in below figure. If the friction between the platform and the body A is 1/3, the acceleration is 0.75 m/sec² 1.00 m/sec² 1.25 m/sec² 0.5 m/sec² 0.75 m/sec² 1.00 m/sec² 1.25 m/sec² 0.5 m/sec² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The maximum velocity of a body vibrating with a simple harmonic motion of amplitude 150 mm and frequency 2 vibrations/sec, is 1.885 m/sec 18.85 m/sec 188.5 m/sec 0.18845 m/sec 1.885 m/sec 18.85 m/sec 188.5 m/sec 0.18845 m/sec ANSWER DOWNLOAD EXAMIANS APP