Applied Mechanics and Graphic Statics A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be 3t³ - 2t 6t + 2 3t² + 2t 6t - 2 3t³ - 2t 6t + 2 3t² + 2t 6t - 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One Newton force, is 10⁴ dynes 10⁶ dynes 10³ dynes 10⁵ dynes 10⁴ dynes 10⁶ dynes 10³ dynes 10⁵ dynes ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Equation of motion of a point in a straight line, is v = u + ft 2fS = v² - u² All listed here S = ut + ½ ft² v = u + ft 2fS = v² - u² All listed here S = ut + ½ ft² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 - M1)/(M1 + M2) T = g(M2 + M1)/(M2 - M1) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The equation of motion of a particle starting from rest along a straight line is x = t3 - 3l2 + 5. The ratio of the velocities after 5 sec and 3 sec will be 5 3 4 2 5 3 4 2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The diagram showing the point of application and line of action of forces in their plane is called Vector diagram Funicular diagram Force diagram Space diagram Vector diagram Funicular diagram Force diagram Space diagram ANSWER DOWNLOAD EXAMIANS APP
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