Refrigeration and Air Conditioning A one tonne refrigerating machine means that One tonne of ice when melts from and at 0° C in 24 hours, the refrigeration effect is equivalent to 210 kJ/min One tonne is the total mass of machine One tonne of water can be converted into ice One tonne refrigerant is used One tonne of ice when melts from and at 0° C in 24 hours, the refrigeration effect is equivalent to 210 kJ/min One tonne is the total mass of machine One tonne of water can be converted into ice One tonne refrigerant is used ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The specific humidity during heating and humidification process. Decreases Increases Remains constant None of these Decreases Increases Remains constant None of these ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning For proper refrigeration in a cabinet, if the temperature and vapour pressure difference between cabinet and atmosphere is high, then Perfectly tight vapour seal should be used Bigger cabinet should be used Refrigerant with lower evaporation temperature should be used Smaller cabinet should be used Perfectly tight vapour seal should be used Bigger cabinet should be used Refrigerant with lower evaporation temperature should be used Smaller cabinet should be used ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The C.O.P. of an absorption type refrigerator is given by (where T₁ = Temperature at which the working substance receives heat, T₂ = Temperature of cooling water, and T₃ = Evaporator temperature) [T₁ (T₂ - T₃)] / [T₃ (T₁ - T₂)] [T₃ (T₁ - T₂)]/ [T₁ (T₂ - T₃)] [T₃ (T₂ - T₃)] / [T₁ (T₁ - T₂)] [T₁ (T₁ - T₂)] / [T₃ (T₂ - T₃)] [T₁ (T₂ - T₃)] / [T₃ (T₁ - T₂)] [T₃ (T₁ - T₂)]/ [T₁ (T₂ - T₃)] [T₃ (T₂ - T₃)] / [T₁ (T₁ - T₂)] [T₁ (T₁ - T₂)] / [T₃ (T₂ - T₃)] ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The power per tonne of refrigeration is O.P/3.5 3.5 × C.O.P. 3.5/C.O.P. None of these O.P/3.5 3.5 × C.O.P. 3.5/C.O.P. None of these ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning In order to cool and dehumidify a stream of moist air, it must be passed over the coil at a temperature Of adiabatic saturation of incoming stream Which lies between the dry bulb and wet bulb temperatures of the incoming stream Which lies between the wet bulb and dew point temperatures of the incoming stream Which is lower than the dew point temperature of the incoming stream Of adiabatic saturation of incoming stream Which lies between the dry bulb and wet bulb temperatures of the incoming stream Which lies between the wet bulb and dew point temperatures of the incoming stream Which is lower than the dew point temperature of the incoming stream ANSWER DOWNLOAD EXAMIANS APP
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