Electromagnetic Field Theory A magnetic field B = 5 × 10-2 uz T exerts a force on 0.02 m conductor along the x-axis. The conductor carried a current of 5 mA in the – ux direction. What force must be applied to the conductor to hold it in position 5 × 10-5 ux N. 5 × 10-5 uz N. 5 × 10-5 uy N. - 5 × 10-5 uy N. 5 × 10-5 ux N. 5 × 10-5 uz N. 5 × 10-5 uy N. - 5 × 10-5 uy N. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory According to Coulomb’s law, the force of attraction or repulsion, between to electrical charges is directly proportional to the square of the distance between them. inversely proportional to the square of the distance between them. inversely proportional to the distance between them. directly proportional to the distance between them. directly proportional to the square of the distance between them. inversely proportional to the square of the distance between them. inversely proportional to the distance between them. directly proportional to the distance between them. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory Whenever the magnetic flux changes with respect to an electric conductor or a coil, an EMF is induced in the conductor is Faraday’s second law third law fourth law first law second law third law fourth law first law ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory Coulombs law for the force between electric charges most closely resembles with Gauss theorem. Newtons law of gravitation. Law of conservation of energy. Newtons law of motion. Gauss theorem. Newtons law of gravitation. Law of conservation of energy. Newtons law of motion. ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory Radiation intensity in a given direction is the Power radiated per square metre Power radiated per unit solid angle in that direction Energy radiated per square metre None of these Power radiated per square metre Power radiated per unit solid angle in that direction Energy radiated per square metre None of these ANSWER DOWNLOAD EXAMIANS APP
Electromagnetic Field Theory A magnetic vector potential is given by the expression A = (- cos x) (cos y) uz. The flux density at the origin is – 2 ux. – uy. 0. 2 ux. – 2 ux. – uy. 0. 2 ux. ANSWER DOWNLOAD EXAMIANS APP
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