Applied Mechanics and Graphic Statics A funicular polygon cannot be made to pass through Two specified points One specified point More than three specified points Three specified points Two specified points One specified point More than three specified points Three specified points ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A system of coplanar forces is in equilibrium when Both force polygon" and funicular polygon close Funicular polygon closes All the forces are concurrent Force polygon closes Both force polygon" and funicular polygon close Funicular polygon closes All the forces are concurrent Force polygon closes ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rigid body is in a stable equilibrium if the application of any force None of above Neither raises nor lowers the CG of the body Can raise the CG of the body but cannot lower it Tends to lower the CG of the body None of above Neither raises nor lowers the CG of the body Can raise the CG of the body but cannot lower it Tends to lower the CG of the body ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two forces each equal to ‘T’ in magnitude act at right angles, their effect may be neutralized by a third force acting along their bisector in opposite direction whose magnitude will be √2 T 2 T 3 T 1/2 T √2 T 2 T 3 T 1/2 T ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball of mass 250 g moving on a smooth horizontal table with a velocity of 10 m/sec hits an identical stationary ball ‘B’ on the table. If the impact is perfectly plastic, the velocity of the ball ‘B’ just after impact would be None of these 5 m/sec Zero 10 m/sec None of these 5 m/sec Zero 10 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane(α) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by g(M1 + M2 sin α)/(M1 + M2) m/sec g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M1 - M2 sin α)/(M1 + M2) m/sec² ANSWER DOWNLOAD EXAMIANS APP
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