C Programming A function 'p' that accepts a pointer to a character as argument and returns a pointer to an array of integer can be declared as int(*p(char *))[] int *p(char *)[] int (*p) (char *)[] None of these. int(*p(char *))[] int *p(char *)[] int (*p) (char *)[] None of these. ANSWER DOWNLOAD EXAMIANS APP
C Programming String concatenation means - Comparing the two strings to define the larger one. Combining two strings. Extracting a substring out of a string. Partitioning the string into two strings. Merging two strings. Comparing the two strings to define the larger one. Combining two strings. Extracting a substring out of a string. Partitioning the string into two strings. Merging two strings. ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output of the following program?#include#define prod(a,b) a*bvoid main(){ int x=3,y=4; printf("%d", prod(x+2,y-1));} 12 10 11 15 None of these 12 10 11 15 None of these ANSWER DOWNLOAD EXAMIANS APP
C Programming What does the following declaration mean?int (*ptr)[10]; ptr is an pointer to array ptr is an array of 10 integers ptr is a pointer to an array of 10 integers ptr is array of pointers to 10 integers ptr is an pointer to array ptr is an array of 10 integers ptr is a pointer to an array of 10 integers ptr is array of pointers to 10 integers ANSWER DOWNLOAD EXAMIANS APP
C Programming char* myfunc(char *ptr){ ptr+=3; return(ptr);}void main(){ char *x, *y; x = "EXAMVEDA"; y = myfunc(x); printf("y=%s", y);}What will be printed when the sample code above is executed? y=AMVEDA y=VEDA y=MVEDA y=EXAMIANS y=EDA y=AMVEDA y=VEDA y=MVEDA y=EXAMIANS y=EDA ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ static int i=5; if(--i){ main(); printf("%d ", i); }} 0 0 0 0 None of These 5 4 3 2 1 Infinite Loop 0 0 0 0 None of These 5 4 3 2 1 Infinite Loop ANSWER DOWNLOAD EXAMIANS APP
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