Electric Circuits A 230V, 50Hz voltage is applied to a coil having L = 5H and R = 2 Ohm in series with capacitance C. When the voltage across the coil is 400V, find the current in the circuit? 0.4583 A. 0.2547 A. 0.1578 A. 0.1465 A. 0.4583 A. 0.2547 A. 0.1578 A. 0.1465 A. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Flux in a magnetic circuit can be compared in an electric circuit to voltage. current. resistance. inductance. voltage. current. resistance. inductance. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In which of the circuits power factor can be zero? both ‘a’ and ‘b’ resistive. inductive. capacitive. both ‘a’ and ‘b’ resistive. inductive. capacitive. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A battery of E Volts is supplying a steady current to a series circuit of total resistance RΩ and inductance L Henry. A part R1 of the total resistance is suddenly short circuited. Find the expression for current flowing through the battery subsequent to the operation. i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} i = {E / R1 - R)}(1- e - (R1 - R) t / L) None of these i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} i = {E / R1 - R)}(1- e - (R1 - R) t / L) None of these i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits For balanced star load, if unbalanced line current are IR, IY, IB equal to - j10, - j10 and - j20 respectively, the neutral current will be equal to (-8.66 - j5) A. (8.66 - j5) A. (8.66 + j5) A. (-9.66 + j5) A. (-8.66 - j5) A. (8.66 - j5) A. (8.66 + j5) A. (-9.66 + j5) A. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Common impurity in battery electrolyte is sodium chloride. iron. lead sulfate. dust. sodium chloride. iron. lead sulfate. dust. ANSWER DOWNLOAD EXAMIANS APP
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