RL Circuits A 12 kΩ resistor is in series with a 90 mH coil across an 8 kHz ac source. Current flow in the circuit, expressed in polar form, is I = 0.3 angle 0° mA. The source voltage, expressed in polar form, is 12.8 angle 20.6° V 0.3 angle 20.6° V 3.84 angle 20.6° V 13.84 angle 69.4° V 12.8 angle 20.6° V 0.3 angle 20.6° V 3.84 angle 20.6° V 13.84 angle 69.4° V ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 1.5 kΩ resistor and a coil with a 2.2 kΩ inductive reactance are in series across an 18 V ac source. The power factor is 564 6.76 55.7 0.564 564 6.76 55.7 0.564 ANSWER DOWNLOAD EXAMIANS APP
RL Circuits When the resistor voltage in a series RL circuit becomes less than the inductor voltage, the phase angle is not affected cannot be determined increases decreases is not affected cannot be determined increases decreases ANSWER DOWNLOAD EXAMIANS APP
RL Circuits If the frequency is halved and the resistance is doubled, the impedance of a series RL circuit halves doubles cannot be determined without values remains constant halves doubles cannot be determined without values remains constant ANSWER DOWNLOAD EXAMIANS APP
RL Circuits If a load is purely inductive and the reactive power is 12 VAR, the apparent power is 6 VA 12 VA 24 VA 0 VA 6 VA 12 VA 24 VA 0 VA ANSWER DOWNLOAD EXAMIANS APP
RL Circuits The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is increased not a factor decreased doubled increased not a factor decreased doubled ANSWER DOWNLOAD EXAMIANS APP
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