RL Circuits A 12 kΩ resistor is in series with a 90 mH coil across an 8 kHz ac source. Current flow in the circuit, expressed in polar form, is I = 0.3 angle 0° mA. The source voltage, expressed in polar form, is 12.8 angle 20.6° V 3.84 angle 20.6° V 0.3 angle 20.6° V 13.84 angle 69.4° V 12.8 angle 20.6° V 3.84 angle 20.6° V 0.3 angle 20.6° V 13.84 angle 69.4° V ANSWER DOWNLOAD EXAMIANS APP
RL Circuits If the frequency is halved and the resistance is doubled, the impedance of a series RL circuit doubles cannot be determined without values remains constant halves doubles cannot be determined without values remains constant halves ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 3.3 kΩ resistor and a 120 mH coil are in parallel. Both components are across a 2 kHz, 12 V ac source. The total current in the circuit is 874 A 8.74 mA 8.74 A 874 mA 874 A 8.74 mA 8.74 A 874 mA ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 470Ω resistor and a 200 mH coil are in parallel. Both components are across a 1.5 kHz ac source. The total admittance of the circuit, in polar form, is 12.60 angle –76° mS 12.18 angle 76° mS 12.18 angle –76° mS 218 angle –76° mS 12.60 angle –76° mS 12.18 angle 76° mS 12.18 angle –76° mS 218 angle –76° mS ANSWER DOWNLOAD EXAMIANS APP
RL Circuits The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is doubled not a factor decreased increased doubled not a factor decreased increased ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 47Ω resistor is in series with an inductive reactance of 120Ω across an ac source. The impedance, expressed in polar form, is 129 angle 31.4° 47 angle 68.6° 129 angle 68.6° 120 angle 68.6° 129 angle 31.4° 47 angle 68.6° 129 angle 68.6° 120 angle 68.6° ANSWER DOWNLOAD EXAMIANS APP
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