Electric Circuits A 100 ohm resistor is directly connected across a 80 V battery. What is the power dissipation? 10 W. 1 W. 5 W. 64 W. 10 W. 1 W. 5 W. 64 W. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In what connection we get neutral? Mesh. Both A and B. Star. Delta. Mesh. Both A and B. Star. Delta. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits One ampere hour charge is equivalent to 36 coulombs. 3600 coulombs. 360 coulombs. 36000 coulombs. 36 coulombs. 3600 coulombs. 360 coulombs. 36000 coulombs. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A battery of E Volts is supplying a steady current to a series circuit of total resistance RΩ and inductance L Henry. A part R1 of the total resistance is suddenly short circuited. Find the expression for current flowing through the battery subsequent to the operation. i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} i = {E / R1 - R)}(1- e - (R1 - R) t / L) None of these i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} i = {E / (R - R1)}[1-(R1 / R) *e- {(R - R1 )t/L} i = {E / R1 - R)}(1- e - (R1 - R) t / L) None of these i = {E / R}[1-(R1 / R) *e - {(R - R1 )*t/L} ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits A voltage of v = 100 sin (wt + π/3) is applied to pure resistor of 30 Ohm. What is the RMS value of current is 4.71. 5.77. 2.36. 1.92. 4.71. 5.77. 2.36. 1.92. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits If 1 A current flows in a circuit, the number of electrons flowing through this circuit is 0.625 × 10 - 19 1.6 × 1019 1.6 × 10 - 19 0.625 × 1019 0.625 × 10 - 19 1.6 × 1019 1.6 × 10 - 19 0.625 × 1019 ANSWER DOWNLOAD EXAMIANS APP
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