Fractions and Decimals 51.3 + 7.078 +1.38 + 0.9 = ? 60.658 80.658 50.658 70.658 60.658 80.658 50.658 70.658 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 51.300 + 7.078 + 1.380 + 0.900 = 60.658
Fractions and Decimals [{(0.1)² - (0.01)²} / {0.0001 + 1 }] is equal to ? 100 75 50 25 100 75 50 25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = (0.01 - 0.0001) / (0.00001 + 1)= (.0099 / .0001) + 1 = 99 + 1= 100
Fractions and Decimals [ .6 x .6 x .6 x .4 x .4 x .4 + 3 x .6 x .4 x (.6 + .4 )] = ? 1 3 2 4 1 3 2 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression =(.6)³ + (.4) ³ + 3 x .6 x .4 x (.6 + .4)= a³ + b³ + 3ab (a+b) = (a+b)³= (.6 + .4)³ = 1³ = 1
Fractions and Decimals The product of 3.5413 x 2.1 is 74.3673 743.673 None of these 7.43673 74.3673 743.673 None of these 7.43673 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For the product of 3.5413 x 2.1Consider 35413 x 21 = 743673Total decimal places = 4 + 1∴ 3.5413 x 2.1=7.43673
Fractions and Decimals If 3 is added to the denominator of a fraction, it becomes 1/3 and if 4 be added to its numerator, It becomes 3/4, then fraction is ? 1/16 None of these 5/12 3/20 1/16 None of these 5/12 3/20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required fraction be p/q∵ p / (q + 3) = 1/3⇒ 3p - q = 3 ...(i)and, (p + 4) / q = 3/4 ⇒ 4p - 3q = -16 ...(ii)Solving these equations, we get p = 5, q = 12∴ Required fraction = 5/12
Fractions and Decimals In the year 2011, Shantanu gets a total of Rs. 3832.5 as his pocket allowance. Find his pocket allowance per day.? Rs. 10.50 Rs. 1.50 Rs. 100.50 Rs. 1000.50 Rs. 10.50 Rs. 1.50 Rs. 100.50 Rs. 1000.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Allowance per day = 3832.5 / 365 = Rs. 10.50
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