Fractions and Decimals (3.65 x 3.65 + 2.35 x 2.35 - 2 x 2.35 x 3.65) / 1.69 = ? 3 4 1 2 3 4 1 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression=[(3.65)² + (2.35)² -2 x 3.65 x 2.35 ] / 1.69=a² + b² - 2ab / 1.69, Where a = 3.65 and b = 2.35=(a - b)² / 1.69 = (3.65 - 2.35)² / 1.69 = (1.3)² / 1.69 = 1.69 / 1.69 = 1
Fractions and Decimals If a fraction is multiplied by itself and then divided by the reciprocal of the same fraction, the result is 18 26/27. Find the fraction. 2 2/3 9 2/3 5 2/3 7 2/3 2 2/3 9 2/3 5 2/3 7 2/3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP If the required fraction be P According to the question (P x P) / (1/P) = 18 26/27⇒ P³ = 512/27∴ P = 8/3 = 2 2/3
Fractions and Decimals (.356 x .365 - 2 x .365 x .106 + .106 x .106) / (.632 x .632 + 2 x .632 x .368 +.368 x .368) = ? .625 .0625 62.5 6.25 .625 .0625 62.5 6.25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(.356)² -2 x .356 x .106 + (.106)²] / [(.632)²+2 x .632 x .368 +(.368)²]= (a² -2ab + b²) / (c²+2cd+d²)= (a - b)² / (c + d)²= (.356 -.106)² / (.632 + .368)²= (.25)² = .0625
Fractions and Decimals The rational number for recurring decimal 0.125125.... is: 125/1000 125/100 125/99 125/999 125/1000 125/100 125/99 125/999 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP _0.125125... = 0.125 =125/999
Fractions and Decimals 0.8 x ? =0.0004 0.05 0.0005 0.00005 0.005 0.05 0.0005 0.00005 0.005 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let 0.8y = 0.0004Then,y = 0.0004 / 0.8 = 0.004 / 8= .0005
Fractions and Decimals In the year 2011, Shantanu gets a total of Rs. 3832.5 as his pocket allowance. Find his pocket allowance per day.? Rs. 1000.50 Rs. 1.50 Rs. 100.50 Rs. 10.50 Rs. 1000.50 Rs. 1.50 Rs. 100.50 Rs. 10.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Allowance per day = 3832.5 / 365 = Rs. 10.50
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