Fractions and Decimals (.23 - .023) / ( .0023 / 23 ) = ? 2770 2077 207 2070 2770 2077 207 2070 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = (.23 - .023) / ( .0023 / 23 ) = .207 / (.0023 / 23) = .207 / .0001=.2070 / .0001 = 2070
Fractions and Decimals What should be subtracted from the multiplication of 0.527 and 2.013 to get 1 ? 0.060851 6085.1 None of these 60.851 0.060851 6085.1 None of these 60.851 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ∵ 0.527 x 2.013 = 1.060851Hence, the required number = 1.060851 - 1 = 0.060851.
Fractions and Decimals 3 / [ 3+ {(0.3 - 3.03) / (3 x 0.91)}] = ? 0.5 2.0 1.5 1.0 0.5 2.0 1.5 1.0 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = 3 / [ 3+ {(0.3 - 3.03) / (3 x 0.91)}] = 3 / [3- { 273 / (3 x 91)}] = 3 / (3-1)= 3 / 2 = 1.5
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2011 2013 2012 2014 2011 2013 2012 2014 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Fractions and Decimals If two-third of two-seventh of a number is 60, then two-fifteenth of that number is 42 71 56 34 42 71 56 34 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the number be X.Then 2/3 x 2/7 x X =60X = 60 x 7 x 3 / 4 = 315Then, 2/15 of 315 = 2/15 x 315 = 42.Hence the required number is 42
Fractions and Decimals Evaluate : [(2.39)² - (1.61)²] / [2.39 - 1.61] 6 4 2 3 6 4 2 3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression=(a² - b²) / (a - b)=[(a + b)(a - b)] / (a - b)= (a + b)= (2.39 + 1.61)= 4
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