Alligation or Mixture problems 15 liters of a mixture contains 20 % alcohol and the rest water. If 3 liters of water be mixed in it, the % of alcohol in the new mixture will be ? 15 18 1 2 16 2 3 17 15 18 1 2 16 2 3 17 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems In the 75 litres of mixture of milk and water, the ratio of milk and water is 4:1. The quantity of water required to make the ratio of milk and water 3:1 is 1 litre 5 litres 4 litres 3 litres 1 litre 5 litres 4 litres 3 litres ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Total quantity of mixture = 75 litre Milk : Water = 4 : 1 3 : 1
Alligation or Mixture problems A milkman has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk. If the cost of pure milk is Rs. 18 per litre, then the profit of the milkman, when he sells all the mixture at cost price, the profit %? 20% 22.5% 33.33% 25% 20% 22.5% 33.33% 25% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP As water costs free, water sold at cost price of milk gives the profit. Required profit % = 5/20 x 100 = 5 x 5 = 25%.
Alligation or Mixture problems An alloy contains copper and tin in the ratio 3 : 2. If 250 gm of copper is added to this alloy then the copper in it becomes double the quantity of tin in it. What is the amount (in gm) of tin in the alloy? 250 500 750 1000 250 500 750 1000 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems Some amount out of Rs. 7000 was lent at 6 % p.a. and the remaining at 4 % p. a. If the total simple interest from both the fractions in 5 years was Rs. 1600, the sum lent at 6 % p. a. was ? Rs. 2000 Rs. 5000 None of these Rs. 3500 Rs. 2000 Rs. 5000 None of these Rs. 3500 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture. 29 % 27 % 21 % 26 % 29 % 27 % 21 % 26 % ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135 X = 27 So, required percentage of benzene = 27 %
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