Fractions and Decimals (0.16)² - (0.12)² = ? .112 1.12 11.2 0.0112 .112 1.12 11.2 0.0112 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? = a² - b² = (a + b)(a - b)Hence, (0.16)² - (0.12)²= (0.16 + 0.12)(0.16 - 0.12)= 0.28 x 0.04 = 0.0112
Fractions and Decimals ( .803 x .647 + .803 x .353 ) = ? 8.03 803 80.3 .803 8.03 803 80.3 .803 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression = ( .803 x .647 + .803 x .353 )= 803 x (.647 + .353)= .803 x 1 = .803
Fractions and Decimals ( .009 / ?) = .01 9 0.9 0.09 0.009 9 0.9 0.09 0.009 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let .009 / x = .01; Then x = .009 / .01=.9 / 1= .9
Fractions and Decimals If √4096 =64 ,then the value of √40.96 + √0.4096 + √0.004096 + √0.00004096 is ? 7.1104 71.104 711.04 .71104 7.1104 71.104 711.04 .71104 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP √4096/100+ √4096/10000 + √4096/1000000 + √4096/100000000=√4096 / 10 + √4096/ 100 + √4096/ 1000 + √4096/ 10000=64/10 + 64/100 + 64/1000 + 64/10000=6.4 + .64 + .064 + .0064 = 7.1104
Fractions and Decimals If 5/6 of a property worth be Rs.976500 then the value of 3/5 of the property is: Rs. 903080 Rs. 703080 None of these Rs. 803080 Rs. 903080 Rs. 703080 None of these Rs. 803080 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the worth of total property be Rs.XWe have to find 3/5 of X.Given that, 5/6 th of the property = Rs.976500i.e., 5/6 x X = 976500X = 976500 x 6/5And, 3/5 of X = 3/5 x 976500 x 6/5 = 18 x 39060 = 703080Hence the answer is Rs. 703080
Fractions and Decimals When 0.36 is written in simplest form, the sum of the numerator and the denominator is : 45 23 12 34 45 23 12 34 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.36 = 36/100 = 9/25.Sum of the numerator and denominator is 9 + 25 = 34
EXAMIANS