Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Here, we have to find the value of 7/(8/9) - (7/8)/9.(7 x 9/8) - [(7/(8 x 9)]63/8 - 7/72[(63 x 9) - 7] / 72567 - 7/72 = 560/72 = 70/9 = 7 7/9.Hence, 7/(8/9) is greater than (7/8)/9 by 7 7/9.
EXAMIANS