Fractions and Decimals 0.000033 / 0.11=? 0.3 0.003 0.0003 0.03 0.3 0.003 0.0003 0.03 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.000033 / 0.11= 0.0033 / 11=.0003
Fractions and Decimals [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] = ? 100 100000 10000 1000 100 100000 10000 1000 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] Which is in form of [(a² + b² + c²)] /[ (a/10)² + (b/10)² + (c/10)²] = 100 x (a² + b² + c²) / (a²+b²+c²) = 100
Fractions and Decimals [{(0.1)² - (0.01)²} / {0.0001 + 1 }] is equal to ? 25 75 50 100 25 75 50 100 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = (0.01 - 0.0001) / (0.00001 + 1)= (.0099 / .0001) + 1 = 99 + 1= 100
Fractions and Decimals Find the value of 1/3 + 1/15 + 1/35 + 1/63 + 1/99 . 5/11 10/11 9/11 7/11 5/11 10/11 9/11 7/11 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 1/3 + 1/15 + 1/35 + 1/63 + 1/99= [1/3 + 1/15] + 1/35 + 1/63 + 1/99 = [6/15 + 1/35] + 1/63 + 1/99= 45/105 + 1/63 + 1/99 = [3/7 + 1/63] + 1/99= 28/63 + 1/99 = 4/9 + 1/99= 44 + 1/99 = 45/99 = 5/11
Fractions and Decimals If 3 is added to the denominator of a fraction, it becomes 1/3 and if 4 be added to its numerator, It becomes 3/4, then fraction is ? 1/16 None of these 3/20 5/12 1/16 None of these 3/20 5/12 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required fraction be p/q∵ p / (q + 3) = 1/3⇒ 3p - q = 3 ...(i)and, (p + 4) / q = 3/4 ⇒ 4p - 3q = -16 ...(ii)Solving these equations, we get p = 5, q = 12∴ Required fraction = 5/12
Fractions and Decimals (3.65 x 3.65 + 2.35 x 2.35 - 2 x 2.35 x 3.65) / 1.69 = ? 2 3 4 1 2 3 4 1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression=[(3.65)² + (2.35)² -2 x 3.65 x 2.35 ] / 1.69=a² + b² - 2ab / 1.69, Where a = 3.65 and b = 2.35=(a - b)² / 1.69 = (3.65 - 2.35)² / 1.69 = (1.3)² / 1.69 = 1.69 / 1.69 = 1
EXAMIANS