Fractions and Decimals 0.000033 / 0.11=? 0.003 0.3 0.0003 0.03 0.003 0.3 0.0003 0.03 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.000033 / 0.11= 0.0033 / 11=.0003
Fractions and Decimals If the numerator of a fraction is increased by 2 and the denominator is increased by 1, the fraction because 5/8 and if the numerator of the same fraction is increased by 3 and the denominator is incr 3/7 1/7 4/7 2/7 3/7 1/7 4/7 2/7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the original fraction be p/q Then, (p + 2) / (q + 1) = 5/8⇒ 8p - 5q = 11 .....(i)Again (p + 3) / (q + 1) = 3/4⇒ 4p - 3q = 9 ...(ii)Solving equations , (i) and (ii), we get ,p = 3 and q = 7∴ Fraction = 3/7
Fractions and Decimals [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] = ? 100000 100 10000 1000 100000 100 10000 1000 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] Which is in form of [(a² + b² + c²)] /[ (a/10)² + (b/10)² + (c/10)²] = 100 x (a² + b² + c²) / (a²+b²+c²) = 100
Fractions and Decimals If 3 is added to the denominator of a fraction, it becomes 1/3 and if 4 be added to its numerator, It becomes 3/4, then fraction is ? None of these 5/12 3/20 1/16 None of these 5/12 3/20 1/16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required fraction be p/q∵ p / (q + 3) = 1/3⇒ 3p - q = 3 ...(i)and, (p + 4) / q = 3/4 ⇒ 4p - 3q = -16 ...(ii)Solving these equations, we get p = 5, q = 12∴ Required fraction = 5/12
Fractions and Decimals 50.8 / 2540 = ? 0.0002 None of these 0.002 0.02 0.0002 None of these 0.002 0.02 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 50.8 / 2540 = 508 / 25400 = 2 / 100 = .02
Fractions and Decimals 16.001 x 11.999 x 99.989 x 0.9 = ? 20924 19347 18764 17280 20924 19347 18764 17280 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? = 16 x 12 x 100 x 0.9 ? = 17280
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